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A Stone Thrown Downward

  • Thread starter Reth0407
  • Start date
5
0
1. Homework Statement
A person throws a stone vertically downward with an initial speed of 16.0m/s from the roof of a building 58.2m above the ground.
What velocity does the stone have at impact?


2. Homework Equations

initial x= 58.2m initial vox=16.0m/s ax= 9.81m/s^2 xfinal=0 vx=?

2a(x-xo)=vx^2-vox^2 to find t= 3.88

vx=vox+axt plug in a number including t=3.88 vx= 54.1



3. The Attempt at a Solution
2 attempts with only 2 attempts left. Please help
 

rude man

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Simplest way is use nergy conservation: initial kinetic energy + loss of potential energy = final kinetic energy.

Other way: v = v0+ gt
h = ∫v(t)dt = v0t + gt2/2 & solve for t = time of fall
h = height of building
Then stick t into the v equation above.
 
5
0
I am still confused on how I would plug the numbers because the instructor have me equations with v and x variables. However, are my numbers correct for time=3.88 s and my vx = 54.1 m/s which I'm sure isn't correct. I'm solving for vx
 

gneill

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1. Homework Statement
A person throws a stone vertically downward with an initial speed of 16.0m/s from the roof of a building 58.2m above the ground.
What velocity does the stone have at impact?


2. Homework Equations

initial x= 58.2m initial vox=16.0m/s ax= 9.81m/s^2 xfinal=0 vx=?

2a(x-xo)=vx^2-vox^2 to find t= 3.88
t doesn't appear in the equation, so how do you obtain t from it :confused: (Also, that doesn't look like a correct value for t for this situation).

However, you can use that equation to find the final velocity, vx. Rearrange the equation to solve for vx.
 
5
0
Ok I got it! LIke gneill said, I could rearrange the equation and solve for vx. Thank you all.
 

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