- #1

ShayanJ

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## Main Question or Discussion Point

There was a tough integral in my math exam that I failed to solve it and so left it blank.After that I used maple's tutor to learn how to solve it.I understood all steps but the first.My problem is that I don't know what function of x, u is.

[tex] \int \! \frac{dx}{ x-\sqrt {9-{x}^{2}}}=\int \!4\,{\frac {u}{-1+{u}^{4}+2\,{u}^{3}+2\,u}} {du}[/tex]

thanks

[tex] \int \! \frac{dx}{ x-\sqrt {9-{x}^{2}}}=\int \!4\,{\frac {u}{-1+{u}^{4}+2\,{u}^{3}+2\,u}} {du}[/tex]

thanks