• Support PF! Buy your school textbooks, materials and every day products Here!

A train: Power and friction

  • Thread starter envscigrl
  • Start date
  • #1
19
0
PROBLEM:
A train with a total mass 2.20E+6kg rises 600m as it travels a distance of 53.0km along a steady slope at a constant speed of 10.0km/hr. The frictional force on the train is 1.400 percent of the weight. Find the kinetic energy of the train.
I did this using K=.5*m*vsquared and got 8501240.
It then asks:

Find the energy dissipated by kinetic friction.

and

Find the power output of the train engines.

I am unsure as to how to find the energy dissipated by kinetic friction. I thought it involved using fk = muk * N
where Mu is the coefficient of friction and N is the normal force. Yet, I could not seem to find the answer.

For the power I tried using P= .5 m Vsquared / t. And finding t from the information given but this also did not work.

Thanks for helping! :smile:
 

Answers and Replies

  • #2
Doc Al
Mentor
44,945
1,206
The energy dissipated by friction is just the work done against friction. Note: They tell you what the frictional force is. No need to calculate it from mu and N.

The engine must provide power to provide the energy needed to raise the train against friction. Figure out how much energy is needed and how much time it takes. Ask yourself: Does the KE of the train change? Does the gravitational PE change? How much work is done against friction?
 

Related Threads on A train: Power and friction

  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
14
Views
7K
Replies
7
Views
8K
  • Last Post
Replies
10
Views
8K
  • Last Post
Replies
11
Views
1K
  • Last Post
Replies
2
Views
3K
Replies
1
Views
385
Replies
3
Views
1K
Replies
1
Views
6K
Top