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A tricky ODE

  1. Nov 6, 2009 #1
    Hi,

    I came across the following differential equation:

    [tex]\sqrt{1+(y')^2}=\frac{d}{dx}\left(y\frac{y'}{\sqrt{1+(y')^2}}\right)[/tex]

    I found possible solutions: [tex]y\left(x\right)=cosh(x+C_{1})[/tex].
    However, this is a second order ODE so there exist a more general solution, with 2 freedom degrees.

    Can anyone find it?

    Thank you.
     
  2. jcsd
  3. Nov 6, 2009 #2

    berkeman

    User Avatar

    Staff: Mentor

    What do you mean "can anyone find it"? Please show us how you have tried to find it so far. This is the PF, not Yahoo answers.
     
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