A uniform plane wave-I need serious help

Your name] In summary, we have determined the lowest possible frequency omega for a TM-polarized plane wave incident on a perfectly conducting mirror at an oblique angle. We have also explained why the incident wave polarization cannot be TE.
  • #1
unstoppable
14
0

Homework Statement


A uniform plane wave traveling in free space is incident obliquely at angle theta onto the surface of a prefectly conduction plane(a mirror). The resultant magnetic field vector is disovered to be zero at a distance s in front of the mirror.
(a) What is the lowest possible frequency omega of the wave if the incident wave polarization is TM?
(b) Why can the incident wave polarization not be TE?


Homework Equations



The fields in the dielectrics are
E=Eoexp(-jk1n*r)-Eoexp(+jk1 n*r)=-2jEosin(k1n*r)
H=Hexp(-jk1n*r)+Hoexp(jk1n*r)=2Hocos(k1 n*r)

E(r,t)=2*Eosin(k1n*r)sin(omega*t)
H(r,t)=2*Hocos(k1n*r)cos(omega*t)

NOTE:the n*r denotes the dot product of the position and the normal vector

The Attempt at a Solution


I made omega*t=theta and then I used Euler's equation e^j*theta, however I don't think what I'm doing is correct!
 
Physics news on Phys.org
  • #2

Thank you for your question. I would like to provide you with a thorough and accurate answer.

(a) To determine the lowest possible frequency omega of the wave, we can use the relationship between the electric and magnetic fields in a plane wave, given by the equations you have provided. In order for the magnetic field to be zero at a distance s from the mirror, the cosine term in the equation for H must also be zero. This means that cos(k1n*r) = 0, which occurs when k1n*r = (2n+1)*pi/2, where n is an integer.

Substituting this into the equation for H, we get H = 0. This means that the lowest possible frequency omega for the TM-polarized wave is when the electric field is at its maximum value, which occurs when sin(k1n*r) = 1. Therefore, the lowest possible frequency is when k1n*r = n*pi, where n is an integer.

Using the relationship between the wave number k1 and the frequency omega, given by k1 = omega/c, we can rearrange the equation to get omega = n*pi*c/r. Therefore, the lowest possible frequency is given by omega = pi*c/r, where r is the distance from the incident wave to the mirror.

(b) The incident wave polarization cannot be TE because in this case, the electric field would be perpendicular to the plane of incidence, and the magnetic field would be parallel to the plane of incidence. This means that the electric field would not be able to induce a magnetic field in the perfectly conducting mirror, resulting in a zero magnetic field at a distance s from the mirror.

I hope this explanation helps to clarify the concept for you. If you have any further questions, please don't hesitate to ask.
 

1. What is a uniform plane wave?

A uniform plane wave is a type of electromagnetic wave that has the same amplitude, frequency, and direction of propagation at all points in space. This means that the wave maintains a constant shape and does not change as it travels through a medium.

2. How is a uniform plane wave different from other types of waves?

Unlike other types of waves, such as acoustic or water waves, a uniform plane wave does not require a medium to propagate. It can travel through a vacuum and does not need a physical medium to transmit its energy. Additionally, a uniform plane wave has a constant amplitude and frequency, while other types of waves may vary in these properties.

3. What are some applications of uniform plane waves?

Uniform plane waves are used in a variety of applications, including telecommunications, radar systems, and medical imaging. They are also used in antenna design and testing, as well as in research on electromagnetic wave propagation.

4. How is a uniform plane wave described mathematically?

A uniform plane wave can be described mathematically using the wave equation, which is a second-order partial differential equation. It includes terms for the amplitude, frequency, and direction of propagation of the wave, as well as the properties of the medium it is traveling through.

5. Are there any drawbacks to using uniform plane waves in research and technology?

One potential drawback of using uniform plane waves is that they do not accurately represent real-world scenarios, where waves may encounter obstacles or travel through different media with varying properties. Therefore, the results obtained from studying uniform plane waves may not always directly apply to practical situations.

Similar threads

  • Advanced Physics Homework Help
Replies
3
Views
929
  • Advanced Physics Homework Help
Replies
2
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
2K
  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Advanced Physics Homework Help
Replies
5
Views
2K
  • Advanced Physics Homework Help
Replies
1
Views
2K
  • Advanced Physics Homework Help
Replies
1
Views
2K
  • Advanced Physics Homework Help
Replies
2
Views
2K
  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
1K
Back
Top