1. The problem statement, all variables and given/known data A uniform solid cylindrical log begins rolling without slipping down a ramp that rises 28.0 above the horizontal. After it has rolled 4.20 m along the ramp, the magnitude of its linear acceleration is closest to 2. Relevant equations 3. The attempt at a solution What I did was mgh=1/2mv^2+1/2Iω^2 mgh=1/2mv^2+1/2[1/2mr^2]ω^2 v=rω mgh=1/2mv^2+1/4mv^2 √4/3gh=v solved for v and got 7.41m/s I then used the constant acceleration equations vx^2=vo+2aΔx solving for a and got 6.54 which is the incorrect answer. Where did I go wrong Thank you!