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Ab2 + Bc2 = Ac2

  1. Aug 13, 2004 #1
    Ab2 + Bc2 = Ac2

    Can you also write this like..

    Ab/Ab + Bc/Bc = Ac/Ac..?
     
  2. jcsd
  3. Aug 13, 2004 #2

    arildno

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    What does your notation mean??
     
  4. Aug 13, 2004 #3
    The question is of this notation is more our less the same.
    If Ab2 and Bc2 have the same value...
    Ab X Ab = Ab2 so Ab2/Ab =Ab
     
  5. Aug 13, 2004 #4

    matt grime

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    err, no since presumably
    Ab/Ab + Bc/Bc = Ac/Ac

    is 1+1=1
     
  6. Aug 13, 2004 #5
    0+0=0, mathematics don't lie...
     
  7. Aug 13, 2004 #6

    arildno

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    But a string of symbols is not necessarily mathematics..
     
  8. Aug 13, 2004 #7

    matt grime

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    so Ab/Ab =0 does it...? oh...
     
  9. Aug 13, 2004 #8
    Ab/Ab=1
    AbxAb=Ab2
    Ab2/Ab=Ab

    Ab2/Ab + Bc2/Bc = Ac2/Ac

    Example..

    2x2/2 + 2x2/2 = Ac2/Ac...
     
  10. Aug 13, 2004 #9

    matt grime

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    do you have a point (other than you don't seem to know any maths) or are you just trolling?
     
  11. Aug 13, 2004 #10
    I try to proof that lightspeed should be zero.
    If Ab ( time) and Bc ( distance ) are always the same for lightspeed.
    Every second 300.000 km more, than is this not possible.
    Only if time and distance are always the same, the speed of light is zero.
    I think I can proof this with phytagoras.

    If Ab2 + Bc2 = Ac2 you also coult write this down as
    Ab/Ab + Bc/Bc = Ac/Ac.

    This is only correct if the speed of light is zero. I think i have a good point here. It's hard to explain.
     
  12. Aug 13, 2004 #11

    Gza

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    I'm not too sure of the notation you are using, so I couldn't really help you out. I think this post belongs in theory development from the looks of it.
     
  13. Aug 13, 2004 #12

    enigma

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    Uh... no...

    a2 + b2 = c2

    [tex]\frac{a^2}{c}+\frac{b^2}{c}=c[/tex]

    [tex]\frac{a}{c} + \frac{b^2}{c*a}=\frac{c}{a}[/tex]

    [tex]\frac{a}{c*b} + \frac{b}{c*a}=\frac{c}{a*b}[/tex]

    Seriously... you need to get through algebra before you go after general relativity.
     
  14. Aug 13, 2004 #13
    I still dont have an answer if Ab2/Ab is the same as AbxAb.
    And why Ab2 + Bc2 = Ac2 is not the same as Ab/Ab + Bc/Bc = Ac/Ac
    I know that this formula only is correct if Ab and Bc are zero. But I think a got some point here.
     
  15. Aug 13, 2004 #14

    enigma

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    Are you kidding? I just did it step by step for you.

    A*A=A^2

    A^2/A = A

    A*A != A^2/A

    See line by line derivation above.

    DNFTT enigma...
     
  16. Aug 13, 2004 #15
    Are you asking if "the product of a number and itself divided by that number" is equal to "the product of a number and itself"? No, unless that number is one.

    The pythagorean theorem relates the lengths of the legs of a right triangle to the length of the hypotenuse. It doesn't say anything about the speed of light.

    Since you're dividing by zero, it's not true then either.

    You're such a killjoy. :wink:
     
  17. Aug 13, 2004 #16
    :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl:
    Right, i could not get the point. Now I see...
     
  18. Aug 13, 2004 #17
    Correct 1+1=1......

    If you do 1 km + 1 sec you got 1 km/sec
    Its correct that 1+1=2 but wat does 2 mean in this example...
     
  19. Aug 13, 2004 #18

    arildno

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    :yuck: splutter :cry: disgust :grumpy:
     
  20. Aug 13, 2004 #19

    Math Is Hard

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    arildno, are you OK?? speak to me!
    arildno..? :eek:
     
  21. Aug 13, 2004 #20
    Ah jeez, I memorized all those other numbers for nothing?
     
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