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Aberration of light

  1. Mar 26, 2013 #1
    1. The problem statement, all variables and given/known data


    http://s22.postimg.org/5vp0p2aox/Untitled.png [Broken]
    2. Relevant equations



    3. The attempt at a solution

    Here is the solution

    I understand everything that must be done after one find the correct transformations for the two coordinates, but I don't understand why the transformation for y' has a minus R at the end. I would think y' = the first two terms x¬0cos + y¬0sin
     
    Last edited by a moderator: May 6, 2017
  2. jcsd
  3. Mar 26, 2013 #2

    mfb

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    Staff: Mentor

    What is ¬?

    The last term comes from the squaring of [highlight]+[/highlight] y0sin(wt) [highlight]-[/highlight] R
     
  4. Mar 26, 2013 #3
    Sorry, the" ¬" of "y¬0" was not suppose to be there. I was typing my post on word and copied and pasted it to the forum. I meant I thought that y' = xocos(wt) + yosin(wt). Why is there a minus R term for y' and not for x'. I understand if it had the R term and we squared y' and x' and add them up and take the square root we would get the numerator shown in the final answer. But I didn't understand why y' had the minus R term in the begging.
     
  5. Mar 27, 2013 #4

    mfb

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    Ah, that R.
    At the considered point in time, you are at (0,R), so you have to subtract this R to get to the origin again.
     
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