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Abosulute Value

  1. May 9, 2005 #1
    Ok, I have to integrate this

    [int a=0 b=3] 1 / sqrt[abs(x-2)] dx

    what should i do ? do the improper integral of 1/-(x-2) and 1/(x-2) ?
  2. jcsd
  3. May 9, 2005 #2


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    Do you know how to work this out:

    [tex]\int \frac{1}{\sqrt{x-2}}dx[/tex]

    If so just split the function you have in to the 2 different functions it is composed of and intergrate over the relevant areas.
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