a uranium atom traveling at speed 4 *
The answer is about 8*10^4 m/s
But, i tried many times and failed.
The Attempt at a Solution
MY thought is that the speed of uranium atom after collision should be the same but in different direction, which means the momentum of hydrogen after collision is 2*p1(p1 is uranium momentum before collision). and use this to calculate the speed by plugging into the formula k = p^2 / 2m