Exploring the Faraday Constant: Understanding its Definition and Importance

In summary, Faraday observed that the same amount of charge is necessary to deposit or separate one mole of any substance. This constant, known as the faraday constant, is represented by the unit C/mole.
  • #1
Jhenrique
685
4
The faraday constant is prayed:
$$\\ 1\; \text{F} = \frac{96 500\;\text{C}}{1\;\text{mol}}$$
(approximately...)


I'm wrong if I say that the faraday constant is:
$$\\ 1\; \text{F} = \frac{96 500\;\text{C}}{1\;\text{mol e}}$$
?
 
Physics news on Phys.org
  • #2
You are right, mole and mol is the same.
 
  • #3
adjacent said:
You are right, mole and mol is the same.

I'm not talking about mol and mole, I'm talking about mol and mol of electron!
 
  • #4
Then that is incorrect then. It is a constant and the units are specifically defined. The fact that it is representative of the charge of a mole of electrons does not change its units to reflect that it is of electrons or the fact that it is just a number.
 
  • #5
Hummm, but 1 mol e ≠ 1 mol p, so the electrical charge associated to 1 mol of eletrons is very different to charge associated to 1 mol of protons.

looks this article: http://en.wikipedia.org/wiki/Stoichiometry#Determining_amount_of_product

Make very much sense say x mol A, y mol B and z mol C than simply say x mol, y mol or z mol.

Until today I don't understand why what is being counted is omited of front of mol...
 
  • #6
The Faraday constant for a mole of electrons is the same as a mole of protons since it does not carry a sign as far as I can see. The Faraday constant could be talking about mole of sodium ions or many other things. We do not include such things in the units. It is just a bookkeeping factor you have to carry forward on your own. It is done all the time in physics. Coulomb's Law is for unit charges but we easily apply a constant prefactor to adjust it for bodies with multiple electrons worth of charge. Yet we do not show this in the units we choose for e the equation.
 
  • #7
Jhenrique said:
Hummm, but 1 mol e ≠ 1 mol p, so the electrical charge associated to 1 mol of eletrons is very different to charge associated to 1 mol of protons.

looks this article: http://en.wikipedia.org/wiki/Stoichiometry#Determining_amount_of_product

Make very much sense say x mol A, y mol B and z mol C than simply say x mol, y mol or z mol.

Until today I don't understand why what is being counted is omited of front of mol...

Saying mol A, mol B, etc.. is like saying the dimensions of an object are 3 meters high, 2 meters wide and 5 meters long. high, wide and long are added to describe what is being measured but they are not part of the unit.
 
  • #8
dauto said:
Saying mol A, mol B, etc.. is like saying the dimensions of an object are 3 meters high, 2 meters wide and 5 meters long. high, wide and long are added to describe what is being measured but they are not part of the unit.

*I think* that when about particles, not should be omited, IMO. Cause you have an infinity of particles, elements and molecules all with different properties...
 
  • #9
You are missing the whole point of introducing this constant.

What Faraday has observed is that the SAME amount of charge (or multiples of it) is necessary to go through the solution in order to separate or deposit one mole of ANY substance.
This "ANY" is reflected in the unit of C/mole. Any mole.

The same charge is carried by a mole of either electrons, protons, sodium ions, chlorine ions, etc.
Or twice as much charge is carried by one mole of calcium ions, copper II ions, etc.
 
  • #10
Or even a mole of moles, with each mole being stripped of exactly one electron.
 
  • #11
nasu said:
You are missing the whole point of introducing this constant.

What Faraday has observed is that the SAME amount of charge (or multiples of it) is necessary to go through the solution in order to separate or deposit one mole of ANY substance.
This "ANY" is reflected in the unit of C/mole. Any mole.

The same charge is carried by a mole of either electrons, protons, sodium ions, chlorine ions, etc.
Or twice as much charge is carried by one mole of calcium ions, copper II ions, etc.

I don't believe!
 
  • #12
OK. No problem. :smile:
 

1. What is the Faraday Constant?

The Faraday Constant is a fundamental physical constant that represents the electric charge per mole of electrons, also known as the Avogadro constant. Its value is approximately 96,485.33289 coulombs per mole.

2. Why is understanding the Faraday Constant important?

The Faraday Constant plays a crucial role in electrochemistry and is used to calculate the amount of substance produced or consumed during an electrochemical reaction. It is also used in other fields such as physics, chemistry, and engineering to study and understand the behavior of electric charges and their interactions.

3. How was the Faraday Constant discovered?

The Faraday Constant was discovered by the English physicist and chemist Michael Faraday in the 19th century. He conducted experiments to determine the relationship between electric current and the amount of substance produced during electrolysis, leading to the discovery of the constant.

4. How is the Faraday Constant measured?

The Faraday Constant can be measured using various methods, including the Faraday's laws of electrolysis, which state that the amount of substance produced during electrolysis is directly proportional to the electric charge passed through the solution. It can also be calculated using other fundamental constants, such as the elementary charge and the Avogadro constant.

5. Can the Faraday Constant change?

No, the Faraday Constant is a fundamental physical constant and its value is fixed. However, slight variations in its value have been observed due to experimental errors. Its value is also affected by changes in the definitions of other fundamental constants, but these changes are very small and do not significantly impact the Faraday Constant.

Similar threads

  • Electromagnetism
Replies
1
Views
1K
Replies
1
Views
753
  • Electromagnetism
Replies
3
Views
2K
  • Electromagnetism
Replies
9
Views
2K
  • Electromagnetism
Replies
5
Views
1K
  • Calculus and Beyond Homework Help
Replies
1
Views
107
  • Precalculus Mathematics Homework Help
Replies
6
Views
499
Replies
13
Views
5K
  • Biology and Chemistry Homework Help
Replies
3
Views
1K
  • Advanced Physics Homework Help
Replies
11
Views
2K
Back
Top