1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

About Hall effect

  1. Apr 23, 2013 #1
    ce089853ba2944128b1ea8a904fc685a.png
    how to interpret this equation physically?
    Why increase of B will lead to increase of V?
    Similar to I,n,e and t
    thx a lot
     
  2. jcsd
  3. Apr 24, 2013 #2

    Simon Bridge

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    The force on the charge carriers in the current is ##\vec{F}=q\vec{v}\times\vec{B}## - if the charge carriers are constrained to move in a conductor, what happens?
     
  4. Apr 24, 2013 #3
    i got how to interpret B and e maybe
    But for n and t,why would it matter the V?
     
  5. Apr 24, 2013 #4
    For a given current, the drift velocity of the carriers is higher if you have lower carrier density (n).
    Actually, if you have lower values of n*e.
    And the Hall voltage depends on the Lorentz force which depends on the velocity.
     
  6. Apr 25, 2013 #5

    Simon Bridge

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    The V is the voltage developed across the "width" of the conductor as a result of the lorentz force. V is what the equation is trying to find.

    So work it out - what makes V bigger? What makes V smaller?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: About Hall effect
  1. The Hall Effect (Replies: 2)

  2. Hall Effect data (Replies: 0)

  3. Hall Effect (Replies: 2)

Loading...