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About Hall effect

  1. Apr 23, 2013 #1
    how to interpret this equation physically?
    Why increase of B will lead to increase of V?
    Similar to I,n,e and t
    thx a lot
  2. jcsd
  3. Apr 24, 2013 #2

    Simon Bridge

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    The force on the charge carriers in the current is ##\vec{F}=q\vec{v}\times\vec{B}## - if the charge carriers are constrained to move in a conductor, what happens?
  4. Apr 24, 2013 #3
    i got how to interpret B and e maybe
    But for n and t,why would it matter the V?
  5. Apr 24, 2013 #4
    For a given current, the drift velocity of the carriers is higher if you have lower carrier density (n).
    Actually, if you have lower values of n*e.
    And the Hall voltage depends on the Lorentz force which depends on the velocity.
  6. Apr 25, 2013 #5

    Simon Bridge

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    The V is the voltage developed across the "width" of the conductor as a result of the lorentz force. V is what the equation is trying to find.

    So work it out - what makes V bigger? What makes V smaller?
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