1. Apr 23, 2013

### asdff529

how to interpret this equation physically?
Why increase of B will lead to increase of V?
Similar to I,n,e and t
thx a lot

2. Apr 24, 2013

### Simon Bridge

The force on the charge carriers in the current is $\vec{F}=q\vec{v}\times\vec{B}$ - if the charge carriers are constrained to move in a conductor, what happens?

3. Apr 24, 2013

### asdff529

i got how to interpret B and e maybe
But for n and t,why would it matter the V?

4. Apr 24, 2013

### nasu

For a given current, the drift velocity of the carriers is higher if you have lower carrier density (n).
Actually, if you have lower values of n*e.
And the Hall voltage depends on the Lorentz force which depends on the velocity.

5. Apr 25, 2013

### Simon Bridge

The V is the voltage developed across the "width" of the conductor as a result of the lorentz force. V is what the equation is trying to find.

So work it out - what makes V bigger? What makes V smaller?