Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

About incompatibility and interference terms

  1. Feb 25, 2008 #1
    In Modern Quantum Mechanics page 44-46, Sakurai compares two experiments:
    1. Here three observables A,B,C are measured. The probability of obtaining the results a,b and c respectively are then :(|<c|b>|^2)(|<b|a>|^2). Summing up over all values of b we'll find [tex]\Sigma[/tex][tex]_{}b/tex](<c|b>|)^2(|<b|a>|)^2
    2. But if we don't measure B,the probability of getting c if we have already got a becomes|<c|a>|^2

    So the two probabilities are different.According to Sakurai the two probabilities are equal is [A,B]=0 or [B,C]=0.
    I'm trying to prove this but haven't been able to find a good proof yet.All help will be appreciated.
     
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted



Loading...
Similar Threads for incompatibility interference terms
I Two coherent sources
B Interference pattern intensity
B What is Quantum Interference?