- #1
KFC
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For harmonic oscillator, let |0> be the ground state, so which statement is correct?
a|0> =|0>
or
a|0> = 0 (number)
where a is the destroy operator
a|0> =|0>
or
a|0> = 0 (number)
where a is the destroy operator
It is the number zero. If a were the identity operator, you would get |0> back.
Neither. [tex] a|0\rangle = [/tex] the zero ket.
No. The zero ket is the zero vector in the state space. [tex] |0\rangle [/tex] is not the zero vector, it's just the vector with eigenvalue [itex] \hbar \omega ( 0 + \frac{1}{2}) [/itex].