θmin=1.22λ/D

## The Attempt at a Solution

(a)θmin=1.22λ/D
(b)θs=1.22(600nm)/30mm=24.4μm but what is spatial resolution and how to calculate it??

SammyS
Staff Emeritus
Homework Helper
Gold Member

## Homework Statement

View attachment 99604

θmin=1.22λ/D

## The Attempt at a Solution

(a)θmin=1.22λ/D
(b)θs=1.22(600nm)/30mm=24.4μm but what is spatial resolution and how to calculate it??
That answer should be in units appropriate for an angle, certainly not μm .

blue_leaf77
Homework Helper
what is spatial resolution and how to calculate it??
It's related to the angular resolution. You can think of the spatial resolution as the arc length of a circle subtended by the angle of angular resolution.

That answer should be in units appropriate for an angle, certainly not μm .

SammyS
Staff Emeritus
Homework Helper
Gold Member
Yes.

It's related to the angular resolution. You can think of the spatial resolution as the arc length of a circle subtended by the angle of angular resolution.
s=rθ, so what is r is this question?object distance? focal length?image distance?

blue_leaf77
Homework Helper
s=rθ, so what is r is this question?object distance? focal length?image distance?
About the circle I was talking about, you can assume it to be centered at the center of the lens and since your image is located at the focal plane, the arc length of interest must touch the focal plane. What will r be?

About the circle I was talking about, you can assume it to be centered at the center of the lens and since your image is located at the focal plane, the arc length of interest must touch the focal plane. What will r be?
Focal lenght?

SammyS
Staff Emeritus