1. Apr 17, 2005

### wundumbbutt

Last edited by a moderator: Apr 21, 2017
2. Apr 17, 2005

### christinono

Last edited by a moderator: Apr 21, 2017
3. Apr 17, 2005

### wundumbbutt

um...kinda how do u know which one you use? sorry im in special ed im super slow in understanding even the simple stuff

4. Apr 17, 2005

### christinono

$$sin\theta = \frac{opposite}{adjacent}$$
$$cos\theta = \frac{adjacent}{hypotenuse}$$
$$tan\theta = \frac{opposite}{adjacent}$$

Use the one which contains the unknown variable and the variable you are given.

5. Apr 17, 2005

### Berislav

Actually, it's:

$$sin\theta = \frac{opposite}{hypotenuse}$$

OP, do you know the sine and cosine rules?

6. Apr 17, 2005

### wundumbbutt

what are the sine and cosine rules?

7. Apr 17, 2005