I've tried squaring both sides, then moving the RHS to the LHS, then factorizing according to a(adsbygoogle = window.adsbygoogle || []).push({}); ^{2}-b^{2}=(a+b)(a-b).

I simplified, and got

((2x+1)/(x+2))((-3/(x+2)) < 0

Then there are 2 cases:

((2x+1)/(x+2)) < 0 and ((-3/(x+2)) > 0

or

((2x+1)/(x+2)) > 0 and ((-3/(x+2)) < 0

I'm not really sure how to go from here...

Please reply ASAP!

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Abs((x-1) / (x+2)) < 1

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