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Absolute derivative

  1. Apr 27, 2012 #1
    1. The problem statement, all variables and given/known data
    Please show that the absolute derivative is a vector field along ##\gamma##, i.e., ##(\frac{d\lambda ^{a'}}{du}+\Gamma^{a'}_{b'c'}\lambda^{b'}\frac{dx^{c'}}{du})=X^{a'}_d(\frac{d\lambda ^{d}}{du}+\Gamma^{d}_{ef}\lambda^{e}\frac{dx^{f}}{du})##
    3. The attempt at a solution
    I don't know how to reduce the following eq. ##(\frac{d\lambda ^{a'}}{du}+\Gamma^{a'}_{b'c'}\lambda^{b'}\frac{dx^{c'}}{du}) = X^{a'}_{bc}\lambda ^b\dot x ^c+X^{a'}_b\dot\lambda ^b-\Gamma ^d_{ef}X^{a'}_d\lambda^eX^{d'}_cX^{e'}_g
    X^f_{d'e'}\dot x^gx^c+\dot x^f\Gamma^d_{ef}X^{a'}_d
    \lambda^e##
    Any comment would be appreciated.
     
  2. jcsd
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