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Well, I have the equation:

[tex]x^2-2x-m|x-1|+m^2=0 (1)[/tex] They ask me what m is so that the equation has solution(s)

Well, I let [tex]t=|1+x|[/tex] and solve the problem with t (no more x) and I have the last equation: [tex]t^2-mt+m^2-1=0[/tex] (2)

in order that (1) has solution(s), (2) must have solution(s) t grater or equal 0

Is that right?, is the action of let t is something make my solution wrong?

Thanks

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# Homework Help: Absolute equation problems.

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