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Absolute Error calculation?

  1. Oct 23, 2006 #1
    How do you calculate the absolute error of an experiment (in moles of acides) when you are given:

    18.59 +/-0.02mL of a 12.85 +/ 0.03M NaOh solution that is going to be neutralized with an unknown acid?

    I'm not sure how to plug it into the equation, or I may be using the wrong equation.
    Thanks:smile:
     
  2. jcsd
  3. Oct 23, 2006 #2
    I took the greatest possible error (18.59 + 12.85) then subtracted it by the maximum error (18.59 + 0.02) + (12.85 + 0.03) but i keep getting the wrong answer, am I suppose to convert the mL to M? (they're both different, but I can't find the mL for NaOh since I don't have the moles) ...
     
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