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Absolute integral

  1. Nov 13, 2009 #1
    [tex]\int^{\pi/2}_{0}|sinx-cos2x| dx[/tex]
    Hi guys i can't seem to get the correct answer for this. What i did was draw the graph of sinx and cos2x and for 0 to [tex]\pi/6[/tex] i use cos2x-sinx since cos2x is higher. From [tex]\pi/6[/tex] to [tex]\pi/2[/tex] i use sinx-cos2x. However i am not able to get the same answer as my book can someone tell me is this the way to do integrals involving the absolute value?
     
    Last edited: Nov 13, 2009
  2. jcsd
  3. Nov 13, 2009 #2

    Dick

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    You've split the integral up correctly. Your problem must be in evaluating the two integrals.
     
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