- #1
hover
- 343
- 0
Homework Statement
Find the absolute maximum and absolute minimum values of f on the given interval.
f(x) = x/(x^2 + 25)
[0, 8]
Homework Equations
taking derivatives are necessary
The Attempt at a Solution
[tex] f(x)= \frac{x}{x^2+25} [/tex]
[tex] f'(x)= \frac{(x^2+25)-x(2x)}{(x^2+25)^2} [/tex]
[tex] f'(x)= \frac{x^2+25-2x^2}{(x^2+25)^2} [/tex]
[tex] f'(x)= \frac{-x^2+25}{(x^2+25)^2} [/tex]
[tex] f'(x)= -x^2+25=0 [/tex]
[tex] 25=x^2 [/tex]
[tex] x=-5,5 [/tex]
[tex] f(0)=0 [/tex] min
[tex] f(5)=1/2 [/tex] max
[tex] f(8)=8/89[/tex]
Those are my answers but i think i am wrong...