Absolute Minimum

  • #1
nickeisenberg
2
0
I found that the local minimum of y=x(e^1/x) is (1,e) but can someone tell me why the absolute minimum is also not (1,e) and can someone tell me why this function does not have an absolute minimum? Thanks
 

Answers and Replies

  • #2
chiro
Science Advisor
4,815
134
I found that the local minimum of y=x(e^1/x) is (1,e) but can someone tell me why the absolute minimum is also not (1,e) and can someone tell me why this function does not have an absolute minimum? Thanks

Hey nickeisenberg and welcome to the forums.

Just to clarify, what is the domain of your function?
 
  • #3
nickeisenberg
2
0
all reals number except 0
 
  • #4
Ultramilk
10
0
y= x (e^1/x)

Think about the two components.
If x -> -∞
x -> -∞
e^(1/x) -> 1 (1/-∞) ~ 0, e^0 = 1
 

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