Absolute polynomial question (driving me nuts)

1. Jan 22, 2005

KataKoniK

|x^2 - 2x - 3| = -(x^2 - 2x - 3), 0 <= x < 3
x^2 - 2x - 3, 3 <= x <=4

how did they get the intervals:
3 <= x <=4 and 0 <= x < 3?

I cannot, for the love of God, know how they determined it.

2. Jan 22, 2005

Hurkyl

Staff Emeritus
Remember the definition of absolute value:

$$|q| := \left\{ \begin{array}{ll} q \quad & q \geq 0 \\ -q \quad & q \leq 0 \end{array}$$

Anyways, it sounds like there's also more to the problem than you gave us.

3. Jan 22, 2005

KataKoniK

Thanks for the help!