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Absolute polynomial question (driving me nuts)

  1. Jan 22, 2005 #1
    |x^2 - 2x - 3| = -(x^2 - 2x - 3), 0 <= x < 3
    x^2 - 2x - 3, 3 <= x <=4

    how did they get the intervals:
    3 <= x <=4 and 0 <= x < 3?

    I cannot, for the love of God, know how they determined it. :mad:
     
  2. jcsd
  3. Jan 22, 2005 #2

    Hurkyl

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    Remember the definition of absolute value:

    [tex]
    |q| := \left\{ \begin{array}{ll} q \quad & q \geq 0 \\ -q \quad & q \leq 0 \end{array}
    [/tex]


    Anyways, it sounds like there's also more to the problem than you gave us.
     
  4. Jan 22, 2005 #3
    Thanks for the help!
     
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