- #1
fishingspree2
- 139
- 0
Hello,
abs(x^2 - 4) < 1
implies that:
x^2 - 4 < 1
and
4 - x^2 < 1
solving first equation for x gives:
-sqrt(5) < x < sqrt(5)
solving second equation for x gives:
-sqrt(3) < x < sqrt(3)
Now, my question is, what does that mean??
How do I give the solution set, without a graphing utility and, if possible, without trial and error?
Thank you
abs(x^2 - 4) < 1
implies that:
x^2 - 4 < 1
and
4 - x^2 < 1
solving first equation for x gives:
-sqrt(5) < x < sqrt(5)
solving second equation for x gives:
-sqrt(3) < x < sqrt(3)
Now, my question is, what does that mean??
How do I give the solution set, without a graphing utility and, if possible, without trial and error?
Thank you