- #1

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## Main Question or Discussion Point

Hello,

abs(x^2 - 4) < 1

implies that:

x^2 - 4 < 1

and

4 - x^2 < 1

solving first equation for x gives:

-sqrt(5) < x < sqrt(5)

solving second equation for x gives:

-sqrt(3) < x < sqrt(3)

Now, my question is, what does that mean??

How do I give the solution set, without a graphing utility and, if possible, without trial and error?

Thank you

abs(x^2 - 4) < 1

implies that:

x^2 - 4 < 1

and

4 - x^2 < 1

solving first equation for x gives:

-sqrt(5) < x < sqrt(5)

solving second equation for x gives:

-sqrt(3) < x < sqrt(3)

Now, my question is, what does that mean??

How do I give the solution set, without a graphing utility and, if possible, without trial and error?

Thank you