- #1
Polymath89
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I'm currently reviewing pre-calculus material and encountered a little problem with an absolute value expression.
|3-x|=x-3
Now the way I learned absolute value expressions was that there's a positive and a negative case. So I got:
3-x=x-3 x=3 and -(3-x)=x-3 gives 0=0. Stupid question, but isn't 0=0 in general valid for all values of x? And I don't understand how you get to the solution x≥3.
|3-x|=x-3
Now the way I learned absolute value expressions was that there's a positive and a negative case. So I got:
3-x=x-3 x=3 and -(3-x)=x-3 gives 0=0. Stupid question, but isn't 0=0 in general valid for all values of x? And I don't understand how you get to the solution x≥3.