Prove the following: if [tex] |a| \leq b [/tex] then [tex] -b \leq a \leq b [/tex] (where [tex] b \geq 0 [/tex]).(adsbygoogle = window.adsbygoogle || []).push({});

So [tex] a \leq b [/tex] and [tex] -a \leq b [/tex]. Then [tex] -b \leq a [/tex] so that [tex] -b \leq a \leq b [/tex].

Suppose that [tex] -b \leq a \leq b [/tex]. Then [tex] a \leq b [/tex] and [tex] -a \leq b [/tex] so that [tex] |a| \leq b [/tex].

Is this a correct proof? You don't have to consider cases (e.g. [tex] a <0, \ a = 0, \ a > 0 [/tex])?

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# Homework Help: Absolute value

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