1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

AC Circuit analysis

  1. Aug 31, 2013 #1
    1. The problem statement, all variables and given/known data
    Two nodes in a network are connected by a line with an impedance of 0.5 + 1.2j Ω. The voltage at the sending end is 33KV and at the receiving end is 32.5 KV with a lag of 1.5° compared to the sending end..

    Calculate the current in the line and the real and reactive power consumed by the line itself.


    2. Relevant equations
    Standard AC circuit analysis equations.


    3. The attempt at a solution

    I think I've got this just want to make sure that I'm not doing anything silly with the angles etc:

    ISR = VS - VR / 0.5 + j1.2 = (33) - (32.5 ∠ -1.5°) / 0.5 + j1.2

    = 763.45 ∠ -8.38°

    Real Power consumed = I2*Re(Z) = (763.45)^2 * 1/2 = 291.5 KW
    Reactive = I2Im(Z) = (763.45)^2 * 1.2 = 700KVAr

    Have I done anything silly? I feel to ask because it seems unusual to me that the reactive power is larger than the real power consumed by the line.

    Many thanks !
     
  2. jcsd
  3. Aug 31, 2013 #2

    gneill

    User Avatar

    Staff: Mentor

    Looks okay.
     
  4. Sep 1, 2013 #3
    Great, thanks a lot !
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: AC Circuit analysis
  1. RLC AC circuit analysis. (Replies: 23)

Loading...