AC Circuit analysis

1. Aug 31, 2013

bd411

1. The problem statement, all variables and given/known data
Two nodes in a network are connected by a line with an impedance of 0.5 + 1.2j Ω. The voltage at the sending end is 33KV and at the receiving end is 32.5 KV with a lag of 1.5° compared to the sending end..

Calculate the current in the line and the real and reactive power consumed by the line itself.

2. Relevant equations
Standard AC circuit analysis equations.

3. The attempt at a solution

I think I've got this just want to make sure that I'm not doing anything silly with the angles etc:

ISR = VS - VR / 0.5 + j1.2 = (33) - (32.5 ∠ -1.5°) / 0.5 + j1.2

= 763.45 ∠ -8.38°

Real Power consumed = I2*Re(Z) = (763.45)^2 * 1/2 = 291.5 KW
Reactive = I2Im(Z) = (763.45)^2 * 1.2 = 700KVAr

Have I done anything silly? I feel to ask because it seems unusual to me that the reactive power is larger than the real power consumed by the line.

Many thanks !

2. Aug 31, 2013

Looks okay.

3. Sep 1, 2013

bd411

Great, thanks a lot !