I need help with determining the current through the 1Ω resistor.
The trouble I have is that the voltage sources are phased as given in picture, and I got stuck on how to deal with these phases when calculating the current with impendance.
I know I need to count the impendance, but I get the wrong answer when I count the current from every source (superposition theorem).
If I look at it through the superposition theorem and current divider rule, I should get the correct answer with regards to current through the 1 Ω resistor.
I am absolutely certain that I don't do the voltage right, i.e. 5 Δ 30 and 5 Δ -30 . Is this correct thinking?
The Attempt at a Solution
Back to superposition theorem, I can count the total impendance for every voltage source. Then I divide the voltage, example
(5 Δ 30) / Z Δ ω = I
From there I go to the current divider rule and count the current through the resistor per source. This is repeated with the upper source as:
(5 Δ -30) / Z Δ ω = I
I've handled these problems well without the voltage phases, but I don't think I handle the voltage phases rather well here. I would really appreciate any pointers on how to proceed!
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