- #1

Rurik1

- 2

- 0

## Homework Statement

I need help with determining the current through the 1Ω resistor.

http://img403.imageshack.us/img403/5422/acex22.jpg [Broken]

The trouble I have is that the voltage sources are phased as given in picture, and I got stuck on how to deal with these phases when calculating the current with impendance.

I know I need to count the impendance, but I get the wrong answer when I count the current from every source (superposition theorem).

## Homework Equations

If I look at it through the superposition theorem and current divider rule, I should get the correct answer with regards to current through the 1 Ω resistor.

I am absolutely certain that I don't do the voltage right, i.e. 5 Δ 30 and 5 Δ -30 . Is this correct thinking?

## The Attempt at a Solution

Back to superposition theorem, I can count the total impendance for every voltage source. Then I divide the voltage, example

(5 Δ 30) / Z Δ ω = I

From there I go to the current divider rule and count the current through the resistor per source. This is repeated with the upper source as:

(5 Δ -30) / Z Δ ω = I

------------------

I've handled these problems well without the voltage phases, but I don't think I handle the voltage phases rather well here. I would really appreciate any pointers on how to proceed!

Last edited by a moderator: