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AC Circuit

  1. Mar 30, 2004 #1
    Hi all,
    can somebody please advise whether the below answer is correct... or am I on the right path??

    Q: What maximum current is delivered by a 2.2 Micro F capacitor when connected to a North American Outlet where Vrms = 110V and f = 60 hz?

    my answer:
    I = Vmax / XC

    XC = 1 / wC
    = 1 / 2 pie 60 * (2.2 * 10E-6)
    = 8.29 ohm

    I = Vmax / XC
    = 110 / 8.29
    = 13.29 A

    Please kindly correct me if I was wrong...
    thanks
    Cseet
     
  2. jcsd
  3. Mar 30, 2004 #2
    You are correct, except for the calculation of Xc. The formula is correct, but you miscalculated it. Xc should be 1.2kohm, and Imax should be 91.2mA.
     
  4. Mar 30, 2004 #3
    Hi Chen,
    thanks alot, you're a GEM!
    cseet
     
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