A)) A choke boil placed in series with an electric lamp in an AC circuit causes the lamp to become dim. Why? B)) A variable capacitor "added" in this circuit maybe adjusted until the lamp glows with normal brilliance. Explain how this is possible ATTEMPT: If V is the voltage of alternating source, and I is the current flowing when no inductor or capacitor is connected, then I 1=V/R If now a choke of inductive reactance Xl is placed in series with the electric lamp, the new impedance of the circuit will be Z 1=underroot<Rsquare + Xlsquare> Therefore current flowing will be I 2=V/[underroot<Rsquare + Xlsquare>] From the comparison of equations of current, we see that I 2 < I 1 and that is why the electric lamp is dimmed on placing a choke in the circuit. When a variable capacitor is added in series, Xc opposes Xl and thus Z 2=underroot<Rsquare + (Xlsquare-Xcsquare)> Therefore, I 3=V/[underroot<Rsquare + (Xlsquare-Xcsquare)>] If Xl = Xc, then Z 2=R And current becomes equal to I 1 as if there's no reactance in the circuit and hence the lamp glows with normal brilliance. Can you check whether this is a correct explanation?