Uncovering the Unknown Circuit Element: An Exploration

In summary: So taking the average of those values results in 0. Therefore, increasing the frequency will cause the amplitude of the current to increase, which in turn will help determine whether the unknown element is an inductor or a capacitor.In summary, the problem involves analyzing a circuit with an AC source, a resistor, and an unknown element (which could be an inductor or a capacitor). The voltage amplitude across the AC source is given as 100, and the root-mean-square current is given as 14.1 A. Using the graph and calculations, the angular frequency and reactance of the unknown element can be determined. The question asks whether the element is an inductor or a capacitor, and the
  • #1
hyddro
74
2
Hi, so I have a homework problem and I don't know how to approach. I am given a circuit, with an AC source, a resistor ( 2 Ω) and a unknown circuit element (that could be an inductor or a capacitor).
I am also given a graph with the Voltage amplitud across the AC source (Which happens to be 100)., I am given the I_ave, which i converted to I ( 20 A). From the graph I calculated the angular frequency (about 340 rad/s). I also found the reactance of the unknown element. Then the question ask for the unknown element: is it an inductor or a capacitor? They also give a hint: they say that increasing the current will help you find whether is an inductor or a capacitor? (How so?)

I am stuck here, I don't know how to do this. I tried doing a phasor diagram but I doesn't seem to help. I just don't know what they mean by 'increasing the current'. Doesn't the current increase by itself? or do they mean the I amplitude? And how would that help me find the element?

Related equations.

V = I Z ( Z = sqrt( R^2 + (XL - XC )^2)
i=I cos(wt)
v_r = IR cos(wt)
w = 2∏*f

Any help will be appreciated.
 
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  • #2
hyddro said:
Hi, so I have a homework problem and I don't know how to approach. I am given a circuit, with an AC source, a resistor ( 2 Ω) and a unknown circuit element (that could be an inductor or a capacitor).
I am also given a graph with the Voltage amplitud across the AC source (Which happens to be 100)., I am given the I_ave, which i converted to I ( 20 A). From the graph I calculated the angular frequency (about 340 rad/s). I also found the reactance of the unknown element. Then the question ask for the unknown element: is it an inductor or a capacitor? They also give a hint: they say that increasing the current will help you find whether is an inductor or a capacitor? (How so?)

I am stuck here, I don't know how to do this. I tried doing a phasor diagram but I doesn't seem to help. I just don't know what they mean by 'increasing the current'. Doesn't the current increase by itself? or do they mean the I amplitude? And how would that help me find the element?

Related equations.

V = I Z ( Z = sqrt( R^2 + (XL - XC )^2)
i=I cos(wt)
v_r = IR cos(wt)
w = 2∏*f

Any help will be appreciated.

Can you post the exact question (preferably scanned)? It's a bit hard to understand exactly what they are saying and asking...
 
  • #3
Sorry, here it is. Ty.
 

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  • #4
Much better :smile:

They say increase the *frequency* of the source, and this is what causes Irms to increase. So that tells you whether the component is a capacitor or inductor. Which is it and why? What are the formulas for the impedance of an inductor and a capacitor?
 
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  • #5
thanks for replying!
Ok, so the impedance for both would be Z = sqrt ( R^2 + X^2) , where X can be either the impedance of a capacitor or an insulator.

So for a capacitor, Z = sqrt ( R^2 + (1/wC)^2) and for the insulator Z = sqrt(R^2 + (wL)^2)...

ok I see now how the angular frequency would change the impedance. If w increases, then Z for a capacitor decreases, if w increases with an inductor then Z increases.

So now what? I don't know neither the capacitance nor the inductance of the element and also, do I have to increase the w to a specific value? or can it be arbitrary? (say 400rad/s)

thank youEDIT: Oh, but I can find them cause I know the angular frequency and the reactance of the element.
I don't have the actual reactance with me now (I left my homework at school and I am at home now) Let's pick an arbitrary value, say that the reactance of the element is 40 Ohms.

Then Xc = 1/wC so C=1/wXc (C = 1/340*40) right? similarly, XL = wL, so L = XL/w (L=340/40)...

is this right?
 
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  • #6
How did you determine the reactance of the 'element'? You can only determine it by I = V/Z.
 
  • #7
EWell, there has to be only one element, so either Xc or Xl = 0, if one of the =0 then the other is present. Z = sqrt( R^2 + (Xl-Xc)^2), which is either sqrt( R^2 + Xl^2) or Sqrt( R^2 + Xc^2) , or simply sqrt(R^2 + X^2)
where X is either 1/wC or wL.EDIT: In case you meant the actual value, V=100, I=20A so Z =5 = Sqrt(2^2 + X^2) , and just solve for X.

EDIT2: so I actually found the angular frequency and X for the element again. w=314.2 rad/s and X=sqrt(21)=4.58 ohms
 
  • #9
hyddro said:
...

, I am given the I_ave, which i converted to I ( 20 A) ...

...They also give a hint: they say that increasing the current will help you find whether is an inductor or a capacitor ...

By the way:

Not only does the problem say to increase the frequency rather than the current, the problem states that the root-mean current is 14.1 A . So, you were given the r.m.s current, not the average current. (The average current is zero.)

You were correct in converting the r.m.s current of 14.1 A to a sinusoidal amplitude of 20 A .
 
  • #10
SammyS said:
By the way:

Not only does the problem say to increase the frequency rather than the current, the problem states that the root-mean current is 14.1 A . So, you were given the r.m.s current, not the average current. (The average current is zero.)

You were correct in converting the r.m.s current of 14.1 A to a sinusoidal amplitude of 20 A .


Thank you, yes I forgot that they were actually giving me the RMS current. You mention something interesting though, the average current is zero. This is because the current oscillates between 20 and -20 right? so the average is 0. Just making sure I know my facts. Ty.
 
  • #11
hyddro said:
Thank you, yes I forgot that they were actually giving me the RMS current. You mention something interesting though, the average current is zero. This is because the current oscillates between 20 and -20 right? so the average is 0. Just making sure I know my facts. Ty.
Yes.

Before you scanned and posted the exact question, I was very puzzled regarding that value for average current.
 
  • #12
Oh ok thank you. I am trying to approach this problem in so many different ways that I got stuck already, So here is my attempt to solving this.
1. We know that if w increases, I increases. I = V/Z , so in order for I to increase, Z has to decrease (as V is constant). (holy crap my head is hurting at this point) Now, for Z to decrease (due to an increase in w) the element must be a capacitor because Z = Sqrt(2^2 + (1/wc)^2), if w increases then Z decreases, hence I increases. Is this analysis correct? It sounds ok to me, but there is one thing tough, why would they say 'increasing w would result on an increase on I' Clearly, for an inductor, increasing w will result on a greater Z, hence I decreases (cause I=V/Z). Any ideas? Thank you.

EDIT: Wait, now that I read the problem, I think they say the Current increases due to the increase in w. Are they saying that they actually increased w and what they saw was that I(rms) increased? If so then the element is a capacitor right?
 
  • #13
hyddro said:
Oh ok thank you. I am trying to approach this problem in so many different ways that I got stuck already, So here is my attempt to solving this.
1. We know that if w increases, I increases. I = V/Z , so in order for I to increase, Z has to decrease (as V is constant). (holy crap my head is hurting at this point) Now, for Z to decrease (due to an increase in w) the element must be a capacitor because Z = Sqrt(2^2 + (1/wc)^2), if w increases then Z decreases, hence I increases. Is this analysis correct? It sounds ok to me, but there is one thing tough, why would they say 'increasing w would result on an increase on I' Clearly, for an inductor, increasing w will result on a greater Z, hence I decreases (cause I=V/Z). Any ideas? Thank you.

EDIT: Wait, now that I read the problem, I think they say the Current increases due to the increase in w. Are they saying that they actually increased w and what they saw was that I(rms) increased? If so then the element is a capacitor right?
Right.
 

1. What is the purpose of "Uncovering the Unknown Circuit Element: An Exploration"?

The purpose of this project is to identify and analyze a previously unknown circuit element and understand its function and characteristics.

2. How is the unknown circuit element identified?

The unknown circuit element is identified through a combination of experimental testing and mathematical analysis. Various electrical measurements are taken and compared to known circuit elements in order to determine its properties.

3. What techniques are used to analyze the unknown circuit element?

Techniques such as impedance analysis, Fourier transform analysis, and frequency response analysis are used to analyze the unknown circuit element. These methods help to understand the behavior and function of the circuit element.

4. What are the potential applications of this research?

The research on the unknown circuit element has potential applications in various fields such as electronics, telecommunications, and renewable energy. It can also contribute to the development of new technologies and improve existing ones.

5. What are the challenges involved in uncovering the unknown circuit element?

Some challenges in this research include accurately identifying and isolating the unknown circuit element, as well as interpreting the results of the analysis. Additionally, the unknown circuit element may have complex and unpredictable behavior, making it difficult to fully understand its function.

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