- #1
kiwikahuna
- 61
- 0
Homework Statement
A circuit contains only 0.197 H inductor. An AC voltage of peak value 166 V and frequency 60.5 Hz is applied to the circuit. When the voltage is 166 V, what is AC current? Answer in units of A.
Homework Equations
The Attempt at a Solution
we know that inductive reactance is XL= ωL
AC voltage peak value IS V = 166 Volts
then AC current is I = V/XL
ω = 2π(FREQUENCY) = 2π(60.5) RAD/SEC
L = INDUCTANCE = 0.197 H
THEN I = 166/ 2π(60.5)*0.197 = 2.22 A
The answer is wrong, could someone tell me what I'm doing wrong? Thank you!