1. The problem statement, all variables and given/known data A circuit contains only 0.197 H inductor. An AC voltage of peak value 166 V and frequency 60.5 Hz is applied to the circuit. When the voltage is 166 V, what is AC current? Answer in units of A. 2. Relevant equations 3. The attempt at a solution we know that inductive reactance is XL= ωL AC voltage peak value IS V = 166 Volts then AC current is I = V/XL ω = 2π(FREQUENCY) = 2π(60.5) RAD/SEC L = INDUCTANCE = 0.197 H THEN I = 166/ 2π(60.5)*0.197 = 2.22 A The answer is wrong, could someone tell me what I'm doing wrong? Thank you!