calculate the power dissipated in a pure resistor of 30 Ohms when the peak vopltage across it from a 100 Hz supply is 22V.(adsbygoogle = window.adsbygoogle || []).push({});

I did P(loss)=I^2R

Vrms=peak voltage/sqroot2=15.558 (i've just used approximate values for the moment)

R=30Ohms

I(resistor)=15.558/30=0.5186

P(loss)=0.5186^2 x 30

=8.069W

but i haven't used the frequency value anywhere, and surely it wouldn't be given if they didn't want you to use it?

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# Homework Help: Ac frequency question

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