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AC sin (B/C) = B

  1. Nov 13, 2009 #1

    tony873004

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    Where A and C are constants. Is there any analytic to solve for B?
     
  2. jcsd
  3. Nov 13, 2009 #2

    mathman

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    There is no analytic solution. The problem can be simplified to be:
    sin(x)/x=k, where x=B/C and k=1/A. When dealing with real values for x and k, |k|>1 has no solution.
     
  4. Nov 13, 2009 #3

    tony873004

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    That's what I suspected. Thanks for confirming.
     
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