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## Homework Statement

v = 60sin(458t + 60º)

Find the voltage of the waveform when t = 5ms

It may be a silly question but I've just started studying ac, just wondering how that + 60º affects the equation?

any help would be appreciated as I've looked everywhere for the method...

## Homework Equations

V = VmSin(2πft)

## The Attempt at a Solution

v = 60sin(458t + 60º)

=> v=60sin(458(5x10-3) + 60º)

=> v=60(0.039957 + sin60º) ? -----> not sure if this is correct

I would appreciate any reply

~Newbie