Accelerated Linear Motion

1. Nov 2, 2003

mcintyre_ie

Hey
Im having some trouble with this Accelerated Linear Motion question. I dont have any clue where i should even start with part (B).

2. Nov 2, 2003

nautica

V(final) = V (original) + acceleration * time

or

Vf - Vo + at

You have only 3 points but 4 velocities, so I assume, your original or initial velocity would be u.

Have you tried this formula???

Nautica

3. Nov 3, 2003

mcintyre_ie

Yes, ive used the formulae before, im having trouble with part two, the juggler question.

4. Nov 3, 2003

HallsofIvy

Part two is relatively simple.

Each ball has acceleration -g= -9.81 m/s2. If we take "v" to be the initial velocity of each ball, then v(T)= v- 9.81T in m/s where T is measured in seconds since the ball was thrown.
In addition, the height of each ball after T seconds is given by
h(T)= vT- (9.81/2)T2.
The ball will continue upward until its velocity is 0: v- 9.81T= 0 so
T= v/9.81. We are told that the height at that time is 3 m:
v(v/9.81)- (9.81/2)(v/9.81)2= v2/(2*9.81)= 3 so