1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Accelerated observers

  1. Nov 8, 2009 #1
    1. The problem statement, all variables and given/known data

    In a laboratory, a pion moves in a circular orbit of radius r and period T as measured
    in the lab frame. How much proper time elapses during one revolution as seen by the

    2. Relevant equations

    Let period = T
    Let radius = r
    Let v = velocity

    (1) v = (2 * pi * r) / T

    Equation of time dilation
    (2) T(proper time) = T / gamma
    where gamma is the usual Lorentz factor

    3. The attempt at a solution

    This is an accelerated problem since the velocity of the pion particle is constantly changing (well, it's direction). I tried to plug in equation (1) into equation (2) but I realised gamma is not constant since the velocity is changing.... so how should I approach this problem. Help!

    Thank you!
  2. jcsd
  3. Nov 10, 2009 #2


    User Avatar
    Homework Helper
    Gold Member

    First, your equation for proper time doesn't look right to me...

    Second, what is the fundamental difference between velocity and speed? Which one of these quantities is [itex]\gamma[/itex] actually dependent on?

    Third, is this really all the information you are given? Are you not told how (or if) the speed of the particle varies along its orbit?
  4. Nov 11, 2009 #3

    Hi there,

    (i) Is it ture that the time dilation equation: Lab frame's time = Lorentz factor * Proper time?

    (ii) hm, velocity is a vector, whereas speed is the magnitude of speed. If the particle is moving round a circle, is it right to say that its magnitude of velocity is constant since only the direction is altering? Can one then infer the Lorentz vector is also a constant since it depends only on the square of velocity?

    (iii) That's all the information I get, it just says the particle is going in a circular orbit of radius r and period T as measured in the lab frame. It's asking me to compute the proper time.
  5. Nov 11, 2009 #4


    User Avatar
    Homework Helper
    Gold Member

    No. Look up the definition of proper time.

    If the particle is undergoing uniform circular motion, then yes, its speed will be constant and so will the Lorentz factor.

    I would assume that the particle is undergoing uniform circular motion then (although you should double check that this is what your professor intended before handing in your assignment).
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Accelerated observers
  1. Moving Observer (Replies: 1)

  2. Commuting observables (Replies: 2)