Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Accelerated reference frames equation derivation question

  1. Feb 26, 2013 #1
    my question comes from the portion of the derivation regarding evaluating the rate of change of the principle axis vectors. this begins by supposing a vector, Q, is rotating about axis n by δθ. Specifically, my question is how from step 4 to step 5 the approximation becomes an equality.

    Q' can be approximated as:
    1. Q' ≈ Q + (|Q|sinα)δθ(in direction of n cross Q)
    2. Q' ≈ Q + |n cross Q|(in direction of n cross Q)δθ
    3. Q' ≈ Q + (n cross Q)δθ
    4. Q' ≈ Q + δθ cross Q

    The derivation then states: "This means that we can express the derivative of this vector as:
    5. (Q'-Q)/dt = (δθ cross Q)/dt
    6. dQ/dt = δθ/dt cross Q
    7. dQ/dt = Ω cross Q
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted



Similar Discussions: Accelerated reference frames equation derivation question
Loading...