Accelerating an electron through a pot. diff.

1. Nov 4, 2004

Romperstomper

An electron is accelerated through a potential difference of 240V, what is it's speed?

I used energy conservation to find it.

So, here's what I did:
$$0 = \frac{1}{2} m\Delta v^2 + q\Delta V$$

$$240V*(1.6*10^-19C) = \frac{1}{2} * (9.1*10^-31kg )* V^2$$

$$V = 9.2*10^6 m/s$$

Is this correct, or am I doing something wrong?

2. Nov 4, 2004

Staff: Mentor

Looks good to me.