An electron is accelerated through a potential difference of 240V, what is it's speed?(adsbygoogle = window.adsbygoogle || []).push({});

I used energy conservation to find it.

So, here's what I did:

[tex] 0 = \frac{1}{2} m\Delta v^2 + q\Delta V[/tex]

[tex]240V*(1.6*10^-19C) = \frac{1}{2} * (9.1*10^-31kg )* V^2[/tex]

[tex]V = 9.2*10^6 m/s[/tex]

Is this correct, or am I doing something wrong?

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# Homework Help: Accelerating an electron through a pot. diff.

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