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Accelerating an electron through a pot. diff.

  1. Nov 4, 2004 #1
    An electron is accelerated through a potential difference of 240V, what is it's speed?

    I used energy conservation to find it.

    So, here's what I did:
    [tex] 0 = \frac{1}{2} m\Delta v^2 + q\Delta V[/tex]

    [tex]240V*(1.6*10^-19C) = \frac{1}{2} * (9.1*10^-31kg )* V^2[/tex]

    [tex]V = 9.2*10^6 m/s[/tex]

    Is this correct, or am I doing something wrong?
     
  2. jcsd
  3. Nov 4, 2004 #2

    Doc Al

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    Staff: Mentor

    Looks good to me.
     
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