(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two wooden crates rest on top of one another. The smaller top crate has a mass of m1 = 22 kg and the larger bottom crate has a mass of m2 = 94 kg. There is NO friction between the crate and the floor, but the coefficient of static friction between the two crates is μs = 0.75 and the coefficient of kinetic friction between the two crates is μk = 0.6. A massless rope is attached to the lower crate to pull it horizontally to the right (which should be considered the positive direction for this problem). The rope is pulled with a tension T = 239 N (which is small enough that the top crate will not slide).

What is the frictional force the lower crate exerts on the upper crate?

2. Relevant equations

F_{fr}=μmg

F_{net}=ma

3. The attempt at a solution

if F(net)=T, then ma=T, and (94+21)a=239, a=2.08m/s^{2}.

I really am not sure how to proceed from here to find the force of friction exerted by the lower block on the upper block....I would really appreciate some help! Thanks!

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# Homework Help: Accelerating blocks

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