Accelerating Wedge Problem, Help!!! 1. The problem statement, all variables and given/known data A 45degree wedge is pushed along a table with constant acceleration A. A block of mass m slides without friction on the wedge. Find its acceleration. As always, find your result in an inertial frame. 2. Relevant equations (x - X) = (h - y)cot (theta) 3. The attempt at a solution I used the equation (x - X) = (h - y)cot (theta) x = horizontal distance from the original place to the block X = horizontal distance from the original place to the wedge h = height of the wedge y = vertical distance from the ground to the block Since the angle is 45 degree, cot (theta) = 1 and after differentiating twice gives, x.. - X.. = -y.. (.. means twice differentiated) And X.. = A (the accel. of the wedge), so y.. = A - x.. And since y.. is not affected by A, isnt y.. just -g? the answer clue in the book says "If A = 3g, y.. = g Please Help!!