A 50-kg crate is pulled across the ice with a rope. A force of 80 N is applied at an angle of 36° with the horizontal. Neglecting friction, calculate
(a) the acceleration of the crate.
(b) the upward force the ice exerts on the crate as it is pulled.
law of Cosines
law of sines
The Attempt at a Solution
I have the upward force "Fay" which is 443N
using the law of sines 80sin36 = 443N which is the vertical force and usig the law of cosines the horizontal is 64.72N
I am not sure how to calculate the acceleration