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Find the acceleration experienced by each of the two masses shown in the picture below if the coefficient of friction between the 7 kg mass and the plane is .25 ?

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In the picture, is the force of fiction go that way ?

http://img515.imageshack.us/img515/893/img3394dj7.jpg [Broken]

m1 = 7kg u = .25

m2 = 12kg

F (per) = F (normal)

F (per) = 68.6 cos 37 = 54.8 N

F (parallel) = 68.66 sin 37 = 41.3 N

F net = (12*9.8) - 1.75 = 115.85 N

115.85 / 19 = 6.1 m/s2

So 7 kg is accelerate at 6.1 m/s2 and 12 kg is the same but in the negative direction.

Is this right ?

------------

In the picture, is the force of fiction go that way ?

http://img515.imageshack.us/img515/893/img3394dj7.jpg [Broken]

m1 = 7kg u = .25

m2 = 12kg

F (per) = F (normal)

F (per) = 68.6 cos 37 = 54.8 N

F (parallel) = 68.66 sin 37 = 41.3 N

F net = (12*9.8) - 1.75 = 115.85 N

115.85 / 19 = 6.1 m/s2

So 7 kg is accelerate at 6.1 m/s2 and 12 kg is the same but in the negative direction.

Is this right ?

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