Acceleration Due To Gravity

  • #1
1. The problem statement.


a = 1/(1+C) g sine pheta


Rearrange equation to solve for g.


My attempt of the solution is:


g = (a+c)/sine pheta

What confuses me is whether or not g sine pheta are all clumped together or if it's just g x sine pheta. Thanks!
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
6,230
31
Well gsinθ = g*sinθ

although I can't tell if your question is


[tex]a = \frac{1}{(1+C)g sin \theta} \ or \ a=\frac{1}{1+C}* gsin \theta[/tex]
 
  • #3
Ah, ok, thanks. It's the second one.
 
  • #4
drizzle
Gold Member
366
57
Ah, ok, thanks. It's the second one.
if so, then:


g = (a+c)/sine pheta
that's not correct,

[tex]
\ a=\frac{1}{1+C}* gsin \theta [/tex]

[tex] \ a{(1+C)}=gsin \theta [/tex]
[tex] \ {(a+aC)}= gsin \theta [/tex]
then
[tex] \ g=\frac{a+aC}{sin \theta}
[/tex]
 

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