# Acceleration Due To Gravity

1. The problem statement.

a = 1/(1+C) g sine pheta

Rearrange equation to solve for g.

My attempt of the solution is:

g = (a+c)/sine pheta

What confuses me is whether or not g sine pheta are all clumped together or if it's just g x sine pheta. Thanks!

rock.freak667
Homework Helper
Well gsinθ = g*sinθ

although I can't tell if your question is

$$a = \frac{1}{(1+C)g sin \theta} \ or \ a=\frac{1}{1+C}* gsin \theta$$

Ah, ok, thanks. It's the second one.

drizzle
Gold Member
Ah, ok, thanks. It's the second one.
if so, then:

g = (a+c)/sine pheta

that's not correct,

$$\ a=\frac{1}{1+C}* gsin \theta$$

$$\ a{(1+C)}=gsin \theta$$
$$\ {(a+aC)}= gsin \theta$$
then
$$\ g=\frac{a+aC}{sin \theta}$$