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Acceleration Due To Gravity

  1. Sep 21, 2009 #1
    1. The problem statement.


    a = 1/(1+C) g sine pheta


    Rearrange equation to solve for g.


    My attempt of the solution is:


    g = (a+c)/sine pheta

    What confuses me is whether or not g sine pheta are all clumped together or if it's just g x sine pheta. Thanks!
     
  2. jcsd
  3. Sep 21, 2009 #2

    rock.freak667

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    Homework Helper

    Well gsinθ = g*sinθ

    although I can't tell if your question is


    [tex]a = \frac{1}{(1+C)g sin \theta} \ or \ a=\frac{1}{1+C}* gsin \theta[/tex]
     
  4. Sep 21, 2009 #3
    Ah, ok, thanks. It's the second one.
     
  5. Sep 21, 2009 #4

    drizzle

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    Gold Member

    if so, then:


    that's not correct,

    [tex]
    \ a=\frac{1}{1+C}* gsin \theta [/tex]

    [tex] \ a{(1+C)}=gsin \theta [/tex]
    [tex] \ {(a+aC)}= gsin \theta [/tex]
    then
    [tex] \ g=\frac{a+aC}{sin \theta}
    [/tex]
     
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