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Acceleration equation problem

  1. May 12, 2005 #1
    1. Show that the minimum stopping distance for a car travelling at speed v is equal to v^2 / 2*coefficient of friction*g, where the coefficient of static friction is between tires and the road and g is acceleration due to gravity.

    I can re-arrange the equation Vf^2 = Vo^2 + 2ad to look the same as the above equation, since a = *coefficient of friction*g

    Is that all this question is asking for? seems like I'm missing something here

  2. jcsd
  3. May 12, 2005 #2
    Yep, sounds about right to me.
  4. May 12, 2005 #3


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    Unbelivebly,some problems are really that simple.:wink: I'm sure u'll get worse.:tongue2:

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