A 50.0 kg object is pulled along a horizontal surface with a horizontal net force of 250 N. A second object with a mass of 75.0 kg travels 4.00 m while changing its velocity from rest to 4.00 m/s. How many times greater is the acceleration of the 50.0 kg object than that of the 75.0 kg object?
a=Fnet/m, v=d/t, a=v/t
The Attempt at a Solution
i tried finding acceleration of the 50 kg object by a=f/m which was 5m/s2. then to find acceleration of the 75kg object i used t=d/v to find the time so that i can plug it into the a=v/t formula. I got 4.00m/s2 for the 75 kg object. What am i doing wrong?because i cannot find the answer.