A bucket of water which weighs 11.5 Newtons is pulled vertically using two forces. The first of magnitude 9.7 Newtons acts at an angle 53 degrees from the vertical. The second acts at an angle 20 degrees from the vertical. Find the acceleration of the bucket in m/s2. (g = 9.81 m/s^2)(adsbygoogle = window.adsbygoogle || []).push({});

I keep getting 14.03m/s^2 but it's wrong can someone please help.

First I found the sum of Fx = (9.7sin53 + -Tsin20) = 22.65

Then, sum of Fy = (9.7cos53 + Tcos20) = -6.212

Fx + Fy = 16.438

F=ma so, 16.438 divided by (11.5/9.81) = 14.02

What am I doing wrong? ALSO, how do I find the net force acting on the bucket (due to the forces and the weight) in Newtons?

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# Homework Help: Acceleration help

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