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Acceleration of a Bus

  1. Sep 23, 2007 #1
    1. The problem statement, all variables and given/known data
    The acceleration of a bus is given by a (t)= alpha t, where alpha = 1.13 m/s^3 is a constant.

    Part A) If the bus's velocity at time t_1 = 1.01 s is 4.93 m/s, what is its velocity at time t_2 = 2.15 s?

    Part B) If the bus's position at time t_1 = 1.01 s is 6.01 m, what is its position at time t_2 = 2.15 s?

    2. Relevant equations

    Vf = Vo + at

    3. The attempt at a solution
    I am stuck on Part A and Part B. I am applying the Vf = Vo + at equation. I set it up as
    Vf = 4.93 + (alpha * t)(2.15s)

    and the answer that I get is wrong. Anyone have any idea how to approach this? Thanks.
  2. jcsd
  3. Sep 24, 2007 #2


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    Staff Emeritus
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    Gold Member

    Your equation that you are using for part (A) is correct, perhaps if you showed us your numbers we could point out whats going wrong. However, note that part (B) us asking for position, so you need a different kinematic equation.
  4. Sep 24, 2007 #3
    Remember to take the difference of the two times when using v(1.01) as Vo in the equation. It is a very common mistake.

    The real equation: Vf = Vo + a(tf-to) for constant a.
    Last edited: Sep 24, 2007
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