The acceleration of a bus is given by a (t)= alpha t, where alpha = 1.13 m/s^3 is a constant.
Part A) If the bus's velocity at time t_1 = 1.01 s is 4.93 m/s, what is its velocity at time t_2 = 2.15 s?
Part B) If the bus's position at time t_1 = 1.01 s is 6.01 m, what is its position at time t_2 = 2.15 s?
Vf = Vo + at
The Attempt at a Solution
I am stuck on Part A and Part B. I am applying the Vf = Vo + at equation. I set it up as
Vf = 4.93 + (alpha * t)(2.15s)
and the answer that I get is wrong. Anyone have any idea how to approach this? Thanks.