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Acceleration of a pendulum

  1. Nov 18, 2013 #1
    1. The problem statement, all variables and given/known data
    A pendulum has a length of 0.5m and an amplitude of oscillation of 8 degrees, what is maximum vertical acceleration



    2. Relevant equations
    [itex]X=Acos(\omega t + \phi)[/itex]
    [itex]\omega =\frac{2\pi}{T}[/itex]
    [itex]T=2\pi \sqrt{\frac{l}{g}}[/itex]


    3. The attempt at a solution
    Taking the second derivative with respect to time for
    [itex]X=Acos(\omega t + \phi)[/itex] then
    [itex]a=-\omega^2Acos(\omega t + \phi)[/itex]
    [itex]\omega[/itex] can be obtained using [itex]T=2\pi \sqrt{\frac{l}{g}}[/itex] and doing [itex]2\pi[/itex] divided by this, but im unsure how to find [itex]A[/itex] Am I on the right lines? Thanks
     
  2. jcsd
  3. Nov 18, 2013 #2
    What is A in this formula?
    Remember that you need vertical component of acceleration.
     
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